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TS EAMCET · Maths · Ellipse

A line perpendicular to the \(X\)-axis cuts the circle \(x^2+y^2=9\) at \(A\) and the ellipse \(4 x^2+9 y^2=36\) at \(B\) such that \(A\) and \(B\) lie in the same quadrant. If \(\theta\) is the greatest acute angle between the tangents drawn to the curves at \(A\) and \(B\), then \(\tan \theta=\)

  1. A \(\frac{1}{12}\)
  2. B \(\frac{1}{2 \sqrt{6}}\)
  3. C \(\frac{5}{24}\)
  4. D \(\frac{5}{4 \sqrt{6}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{2 \sqrt{6}}\)

Step-by-step Solution

Detailed explanation

Let the equation of line perpendicular to \(X\)-axis cut the circle \(x^2+y^2=9\) at \(A\) is \((3 \cos \alpha, 3 \sin \alpha)\) Equation of tangent at \(A\) is \(x \cos \alpha+y \sin \alpha=3\) Slope \(=-\cot \alpha\) Similarly, cut the ellipse \(4 x^2+9 y^2=36\) at \(B\) is…