TS EAMCET · Maths · Functions
Let \(a, b\), and \(c\) be such that \(\frac{1}{(1-x)(1-2 x)(1-3 x)}=\frac{a}{1-x}+\frac{b}{1-2 x}+\frac{c}{1-3 x}\) then \(\frac{a}{1}+\frac{b}{3}+\frac{c}{5}\) is equal to
- A \(\frac{1}{15}\)
- B \(\frac{1}{6}\)
- C \(\frac{1}{5}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{15}\)
Step-by-step Solution
Detailed explanation
We have, \(1=a(1-2 x)(1-3 x)+b(1-x)(1-3 x)…
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