TS EAMCET · Chemistry · Chemical Kinetics
The rate constant of a first order reaction at \(27^{\circ} \mathrm{C}\) is \(10^{-3} \mathrm{~min}^{-1}\). The temperature coefficient of this reaction is 2 . What is the rate constant (in \(\mathrm{min}^{-1}\) ) at \(17^{\circ} \mathrm{C}\) for this reaction?
- A \(10^{-3}\)
- B \(5 \times 10^{-4}\)
- C \(2 \times 10^{-3}\)
- D \(10^{-2}\)
Answer & Solution
Correct Answer
(B) \(5 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
Temperature coefficient, \(=\frac{k_t+10}{k_t}\) \(2=\frac{10^{-3}}{k_t}\) \(k_t=\frac{10^{-3}}{2}=\frac{10 \times 10^{-4}}{2}=5 \times 10^{-4}\)
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