TS EAMCET · Maths · Permutation Combination
Seven scientists \(S_1, S_2, \ldots . ., S_7\) are invited to deliver one lecture each in a conference. The number of ways all the seven lectures can be arranged such that the lecture of \(S_1\) is prior to that of \(S_3\) and the lecture of \(S_3\) is prior to that of \(S_7\) is
- A 35
- B 840
- C 720
- D 210
Answer & Solution
Correct Answer
(B) 840
Step-by-step Solution
Detailed explanation
In order of \(S_1, S_3, \ldots, S_7\) is not to change, then they are to be treated identical in arrangements. So, the required number of \(\begin{aligned} \text { ways } & =\frac{7 !}{3 !} \\ & =7 \cdot 6 \cdot 5 \cdot 4=840 \end{aligned}\)
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