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TS EAMCET · Maths · Parabola

Let \(P\) represent the point \((3,6)\) on the parabola \(y^2=12 x\). For the parabola \(y^2=12 x\), if \(l_1\) is the length of the normal chord drawn at \(P\) and \(l_2\) is the length of the focal chord drawn through \(P\), then \(\frac{l_1}{l_2}=\)

  1. A \(2 \sqrt{2}\)
  2. B 3
  3. C \(4 \sqrt{2}\)
  4. D 5
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \sqrt{2}\)

Step-by-step Solution

Detailed explanation

We know that, length of normal of parabola \(y^2=4 a x\) at \(\left(a t^2, 2 a t\right)=8 a \sqrt{t^2+1}\) and length of focal chord \(=a\left(t+\frac{1}{t}\right)^2\). Point \(P(3,6)\) lie on parabola \(y^2=12 x\) \(\therefore\) Here \(a=3, t=1\) Hence…
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