TS EAMCET · Maths · Three Dimensional Geometry
\(A B C D\) is a parallelogram and \(P\) is the mid-point of the side \(A D\). The line \(B P\) meets the diagonal \(A C\) in \(Q\). Then, the ratio of \(A Q: Q C\) is equal to
- A \(1: 2\)
- B \(2: 1\)
- C \(1: 3\)
- D \(3: 1\)
Answer & Solution
Correct Answer
(A) \(1: 2\)
Step-by-step Solution
Detailed explanation
Let \(Q\) divides \(A C\) and \(B P\) in the ratio \(\lambda: 1\) and \(\mu: 1\) respectively. Now, point \( Q=\frac{\lambda(b+d)+1(0)}{\lambda+1}=\frac{\lambda(b+d)}{\lambda+1}=\frac{\lambda}{\lambda+1} b+\frac{\lambda}{\lambda+1} d \) and…
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