ExamBro
ExamBro
TS EAMCET · Maths · Differentiation

If \(y=\log \left[\tan \sqrt{\frac{2^x-1}{2^x+1}}\right], x\gt0\), then \(\left(\frac{d y}{d x}\right)_{x=1}=\)

  1. A \(\frac{4 \sqrt{2} \log 2}{9 \sin \left(\frac{2}{\sqrt{3}}\right)}\)
  2. B \(\frac{4 \sqrt{3} \log 2}{9 \sin \left(\frac{\sqrt{3}}{2}\right)}\)
  3. C \(\frac{4 \sqrt{3} \log 2}{9 \sin \left(\frac{2}{\sqrt{3}}\right)}\)
  4. D \(\frac{4 \sqrt{2} \log 2}{9 \sin \left(\frac{\sqrt{3}}{2}\right)}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{4 \sqrt{3} \log 2}{9 \sin \left(\frac{2}{\sqrt{3}}\right)}\)

Step-by-step Solution

Detailed explanation

\(y=\log \left[\tan \sqrt{\frac{2^x-1}{2^x+1}}\right] \Rightarrow e^y=\tan \sqrt{\frac{2^x-1}{2^x+1}}\)....(i) Let \(\frac{2^x-1}{2^x+1}=v \Rightarrow v_{x=1}=\frac{1}{3}\)…