TS EAMCET · Physics · Atomic Physics
The ground state energy of hydrogen atom is -13.6 eV . The potential energy of the electron in the first excited state of hydrogen is
- A -6.8 eV
- B -3.4 eV
- C -13.6 eV
- D -27.2 eV
Answer & Solution
Correct Answer
(A) -6.8 eV
Step-by-step Solution
Detailed explanation
For hydrogen atom, \(E_1=-13.6 e V, E_n=\frac{E_1}{n^2} \therefore E_2=\frac{E_1}{4}=-3.4 e V\) \(\therefore\) Potential energy, \(\mathrm{U}_2=2 \mathrm{E}_2=2 \times(-3.4)=-6.8 \mathrm{eV}\)
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