TS EAMCET · Physics · Center of Mass Momentum and Collision
Particle A moving with a velocity \(v=10 \mathrm{~m} / \mathrm{s}\) experienced a head on collision with a stationary particle B of the same mass.Asaresultof collision, thekinetic energyofthesystem decreased by \(1 \%\). The speed of particle A after collision in
- A 10 m/s
- B 0.05 m/s
- C 5 m/s
- D \(10 \sqrt{2} \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) 10 m/s
Step-by-step Solution
Detailed explanation
By law of conservation of momentum \(\mathrm{m} \times 10+0=\mathrm{mV}_1+\mathrm{mV}_2\) \(10=V_1+V_2\)...(i) Now,…
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