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TS EAMCET · Maths · Complex Number

If \(z=x+i y\) is a complex number such that \(\bar{z}^{\frac{1}{3}}=a+i b\), then the value of \(\frac{1}{a^2+b^2}\left(\frac{x}{a}+\frac{y}{b}\right)\) is equal to

  1. A -1
  2. B -2
  3. C 0
  4. D 2
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(B) -2

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