TS EAMCET · Maths · Parabola
The equation of the parabola with focus \((1,-1)\) and directrix \(x+y+3=0\), is
- A \(x^2+y^2-10 x-2 y-2 x y-5=0\)
- B \(x^2+y^2+10 x-2 y-2 x y-5=0\)
- C \(x^2+y^2+10 x+2 y-2 x y-5=0\)
- D \(x^2+y^2+10 x+2 y+2 x y-5=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2-10 x-2 y-2 x y-5=0\)
Step-by-step Solution
Detailed explanation
Let \(P(x, y)\) be any point on the parabola. Since, the distance of \(P\) from the focus \(S(1,-1)\) is equal to its distance from the directrix. \[ \therefore \quad P S=P Q \text { or } P S^2=P Q^2 \] where, \(Q\) is the point on directrix.…
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