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TS EAMCET · Maths · Circle

The locus of the centre of the circle, which cuts the circle \(x^2+y^2-20 x+4=0\) orthogonally and touches the line \(x=2\), is

  1. A \(x^2=16 y\)
  2. B \(y^2=4 x\)
  3. C \(y^2=16 x\)
  4. D \(x^2=4 y\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(y^2=16 x\)

Step-by-step Solution

Detailed explanation

Let the equation of circle be \[ x^2+y^2+2 g x+2 f y+c=0 \] where, centre \((-g,-f)\) The centre of given circle \(x^2+y^2-20 x+4=0\) is \((10,0)\), Condition of two circles cut.…
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