TS EAMCET · Maths · Circle
The area (in sq. units) of the triangle formed by the \(\mathrm{X}\)-axis, the tangent and the normal drawn to the circle \(x^2+y^2=10 x\) at the point \((9,3)\) is
- A \(\frac{75}{4}\)
- B \(\frac{75}{8}\)
- C 75
- D 25
Answer & Solution
Correct Answer
(B) \(\frac{75}{8}\)
Step-by-step Solution
Detailed explanation
\(x^2+y^2-10 x=0\) Equation of tangent at \((9,3)\) \(\begin{aligned} & 9 x+3 y-5(x+9)=0 \\ & T: \quad 4 x+3 y-45=0\end{aligned}\) Slope of tangent \(=\frac{-4}{3}\) and slope of normal \(=\frac{3}{4}\) \(\therefore \quad\) Equation of normal \(y-0=\frac{3}{4}(x-5)\)…
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