TS EAMCET · Maths · Probability
Two players A and B are alternately throwing a coin and a die together. A player who first throws head and 6 wins the game. If A starts the game, then the probability that B wins the game is.
- A \(\frac{12}{23}\)
- B \(\frac{11}{23}\)
- C \(\frac{5}{119}\)
- D \(\frac{12}{119}\)
Answer & Solution
Correct Answer
(B) \(\frac{11}{23}\)
Step-by-step Solution
Detailed explanation
Let \(P(B)\) to wins the game is \(=\frac{1}{12}\) Since, B can win the game in 2nd throw, 4th throw, 6th throw and so on. Hence \(P(B)\) to win the game is…
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