TS EAMCET · Maths · Differentiation
If \(\sin y=\sin 3 t\) and \(x=\sin t\), then \(\frac{d y}{d x}=\)
- A \(\frac{3}{\sqrt{4-x^2}}\)
- B \(\frac{3}{\sqrt{1-x^2}}\)
- C \(\frac{1}{\sqrt{4-x^2}}\)
- D \(\frac{-1}{\sqrt{4-x^2}}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{\sqrt{1-x^2}}\)
Step-by-step Solution
Detailed explanation
\(\sin y=\sin 3 t\) \(\begin{aligned} & t=3 t \\ & y=3 \sin ^{-1} x \\ & \frac{d y}{d x}=\frac{d}{d x} 3 \sin ^{-1} x \\ & =\frac{3}{\sqrt{1-x^2}}\end{aligned}\)
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