TS EAMCET · Maths · Probability
Four boxes \(A, B, C\) and \(D\) contain 5000,3000 , 2000 and 1000 fuses respectively. The percentages of defective fuses in these boxes are \(3 \%, 2 \%, 1 \%\) and \(0.5 \%\) respectively. If a fuse selected at random from one of the boxes is found to be defective, then the probability that it has come from box \(D\) is
- A \(\frac{1}{13}\)
- B \(\frac{4}{65}\)
- C \(\frac{1}{65}\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
Consider the event \(A=\) Box A is selected \(\mathrm{B}=\mathrm{Box} \mathrm{B}\) is selected \(\mathrm{C}=\mathrm{Box} \mathrm{C}\) is selected \(\mathrm{D}=\mathrm{Box} \mathrm{D}\) is selected \(\mathrm{E}=\) Defective fuses \(p(A)=\frac{5000}{11000}=\frac{5}{11}\)…
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