TS EAMCET · Maths · Application of Derivatives
In each of the choices given below, a function and an interval are given. The correct choice having a function and the associated interval for which the Lagrange's mean value theorem is not valid is
- A \(|x|:[1,5]\)
- B \(\log x:[1, e]\)
- C \(\frac{2 x-1}{3 x-4}:[1,2]\)
- D \((x-2)^2(x-4)^2:[2,4]\)
Answer & Solution
Correct Answer
(C) \(\frac{2 x-1}{3 x-4}:[1,2]\)
Step-by-step Solution
Detailed explanation
Let \(f(x)=\frac{2 x-1}{3 x-4},[1,2]\) Since, \(f(x)\) is not defined at \(x=\frac{4}{3} \in[1,2]\) So, Lagrange's theorem is not applicable on \(f(x)\) on \([1,2]\)
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