TS EAMCET · Maths · Straight Lines
Let \(A(1,1), B(1,-1), C(-1,1)\) be the vertices of \(\triangle A B C\). Let \(S\) be the circum-centre, \(O\) be the orthocentre and \(I\) be the incentre of the \(\triangle A B C\). Then \(I S+O S=\)
- A \(4\)
- B \(2\)
- C \(2+2 \sqrt{2}\)
- D \(2+\sqrt{2}\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
It is clear that \(\triangle A B C\) is a right angled triangle at \(A\). \(\therefore\) Circum-centre, \(S=\) Mid-point of hypotenuse \(B C\) \(=\left(\frac{-1+1}{2}, \frac{1-1}{2}\right)=(0,0)\) Orthocentre, \(O=\) Coordinate of vertice at which right angle is there…
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