TS EAMCET · Physics · Rotational Motion
A circular ring of mass \(10 \mathrm{~kg}\) rolls along a horizontal floor. The center of mass of the ring has a speed \(1.5 \mathrm{~m} / \mathrm{s}\). The work required to stop the ring is
- A \(10 \mathrm{~J}\)
- B \(-6 J\)
- C \(14.5 \mathrm{~J}\)
- D \(-22.5 \mathrm{~J}\)
Answer & Solution
Correct Answer
(D) \(-22.5 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Given, mass of a circular ring, \(m=10 \mathrm{~kg}\) speed of centre of mass of the ring i.e, linear speed of ring, \(u=1.5 \mathrm{~m} / \mathrm{s}\) Total initial kinetic energy of rolling ring,…
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