TS EAMCET · Maths · Indefinite Integration
If \(\int \frac{(x-1) d x}{(x+1) \sqrt{x^3+x^2+x}}=A \cdot \tan ^{-1} \sqrt{f(x)}+\) constant, then the ordered pair \((A, f(-1))=\)
- A \((2,1)\)
- B \((2,-1)\)
- C \((1,2)\)
- D \((-2,2)\)
Answer & Solution
Correct Answer
(B) \((2,-1)\)
Step-by-step Solution
Detailed explanation
We have, \(\int \frac{(x-1) d x}{(x+1) \sqrt{x^3+x^2+x}}=A \tan ^{-1} \sqrt{f(x)}+C\) Let \(\begin{aligned} I & =\int \frac{(x-1) d x}{(x+1) \sqrt{x^3+x^2+x}} \\ & =\int \frac{x-1}{x(x+1) \sqrt{x+\frac{1}{x}+1}} d x \end{aligned}\) Put,…
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