ExamBro
ExamBro
TS EAMCET · Maths · Indefinite Integration

If \(\int \frac{(x-1) d x}{(x+1) \sqrt{x^3+x^2+x}}=A \cdot \tan ^{-1} \sqrt{f(x)}+\) constant, then the ordered pair \((A, f(-1))=\)

  1. A \((2,1)\)
  2. B \((2,-1)\)
  3. C \((1,2)\)
  4. D \((-2,2)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((2,-1)\)

Step-by-step Solution

Detailed explanation

We have, \(\int \frac{(x-1) d x}{(x+1) \sqrt{x^3+x^2+x}}=A \tan ^{-1} \sqrt{f(x)}+C\) Let \(\begin{aligned} I & =\int \frac{(x-1) d x}{(x+1) \sqrt{x^3+x^2+x}} \\ & =\int \frac{x-1}{x(x+1) \sqrt{x+\frac{1}{x}+1}} d x \end{aligned}\) Put,…