ExamBro
ExamBro
TS EAMCET · Maths · Permutation Combination

The number of ways of arranging 8 boys and 8 girls in a row so that boys and girls sit alternately is

  1. A 9 !
  2. B \((9 !)(8 !)\)
  3. C \((8 !)^2\)
  4. D \(2 !(8 !)^2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 !(8 !)^2\)

Step-by-step Solution

Detailed explanation

We have, 8 boys and 8 girls. To tal number of arrangements of 8 boys and 8 girls. Sit altemately is \(8 ! \times 8 ! \times 2 !=2 !(8 !)^2\)