TS EAMCET · Maths · Quadratic Equation
The sum of all the real numbers satisfying the equation \(x^2+|x-3|=4\) is
- A 0
- B 1
- C 2
- D -1
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
We have, \[ x^2+|x-3|=4 \] Case I. \(x>3\) \[ \begin{array}{r} x^2+x-3=4 \\ x^2+x-7=0 \\ x=\frac{-1 \pm \sqrt{29}}{2} \end{array} \] \(\therefore\) No solution \[ [\because x>3] \] Case II. \(x < 3\)…
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