TS EAMCET · Maths · Circle
The equation of the circle of radius 5 and touching the co-ordinate axes in third quadrant is
- A \((x-5)^2+(y+5)^2=25\)
- B \((x+5)^2+(y+5)^2=25\)
- C \((x+4)^2+(y+4)^2=25\)
- D \((x+6)^2+(y+6)^2=25\)
Answer & Solution
Correct Answer
(B) \((x+5)^2+(y+5)^2=25\)
Step-by-step Solution
Detailed explanation
Since the circle touches the coordinate axes in third quadrant therefore. centre of the circle is \((-5,-5)\) Then equation of circle is, \((x+5)^2+(y+5)^2=25\).
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