TS EAMCET · Maths · Vector Algebra
If \(\vec{a}\) is a vector such that \(\vec{a} \times \hat{i}=\hat{j}+\hat{k}\) and \(\vec{a} \cdot \hat{i}=1\), then equation of the line passing through the point \(\hat{i}+\hat{j}+\hat{k}\) and parallel to \(\vec{a}\) is
- A \(\vec{r}=(t+1) \hat{i}+(1-t) \hat{j}+(t+1) \hat{k}\)
- B \(\vec{r}=(t+1) \hat{i}-(2 t-1) \hat{j}+t \hat{k}\)
- C \(\vec{r}=\hat{i}+t \hat{j}-t \hat{k}\)
- D \(\vec{r}=5 t \hat{i}+7 t \hat{j}+\hat{k}\)
Answer & Solution
Correct Answer
(A) \(\vec{r}=(t+1) \hat{i}+(1-t) \hat{j}+(t+1) \hat{k}\)
Step-by-step Solution
Detailed explanation
Let \(\vec{a}=x \hat{i}+y \hat{j}+z \hat{k}\)…
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