TS EAMCET · Maths · Trigonometric Ratios & Identities
\(\tan 81^{\circ}-\tan 63^{\circ}-\tan 27^{\circ}+\tan 9^{\circ}\) equals to
- A \(6\)
- B \(0\)
- C \(2\)
- D \(4\)
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \tan 81^{\circ}-\tan 63^{\circ}-\tan 27^{\circ}+\tan 9^{\circ} \\ & =\left(\tan 81^{\circ}+\tan 9^{\circ}\right)-\left[\tan \left(63^{\circ}\right)+\tan \left(27^{\circ}\right)\right] \\ & =\left[\frac{\sin 81^{\circ}}{\cos 81^{\circ}}+\frac{\sin…
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