TS EAMCET · Maths · Vector Algebra
In a quadrilateral \(A B C D\), the point \(P\) divides \(D C\) in the ratio \(1: 3\) internally and \(Q\) is the mid-point of \(A C\). If \(\mathbf{A B}+\mathbf{A D}+\mathbf{B C}-2 \mathbf{D C}=\lambda \mathbf{P Q}\), then the value of \(\lambda\) is
- A -2
- B 2
- C 4
- D -4
Answer & Solution
Correct Answer
(D) -4
Step-by-step Solution
Detailed explanation
We have, \(\mathbf{O P}=\frac{\mathbf{c}+3 \mathbf{d}}{4}\) and \(\mathbf{O Q}=\frac{\mathbf{a}+\mathbf{c}}{2}\) It is given that…
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