TS EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta\) are the roots of the equation \(x+\frac{4}{x}=2 \sqrt{3}\), then \(\frac{2}{\sqrt{3}}\left|\alpha^{2024}-\beta^{2024}\right|=\)
- A \(2^{2024}\)
- B \(2^{2025}\)
- C \(2^{2023}\)
- D \(2^{2023}\)
Answer & Solution
Correct Answer
(B) \(2^{2025}\)
Step-by-step Solution
Detailed explanation
\(x^2-2 \sqrt{3} x+4=0\) Roots \(\alpha, \beta\) are \(\frac{2 \sqrt{3} \pm \sqrt{-4}}{2}=\sqrt{3} \pm i\)…
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