TS EAMCET · Maths · Determinants
For the system \(S\) of linear equations \(x+y+z=3,2 x+2 y-z=3, x+y+\lambda z=1\) the incorrect option among the following statements is
- A \(S\) has infinitely many solutions, if \(\lambda=-1\)
- B \(S\) has no solution, if \(\lambda=-2\)
- C \(S\) has no unique solution for any real \(\lambda\)
- D \(S\) is consistent for all \(\lambda \in R\)
Answer & Solution
Correct Answer
(D) \(S\) is consistent for all \(\lambda \in R\)
Step-by-step Solution
Detailed explanation
We have, \(x+y+z=3\)…
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