TS EAMCET · Maths · Circle
If \(P A\) and \(P B\) are the tangents drawn from the point \(P(1,1)\) to the circle \(x^2+y^2+g x+g y-2=0\) with \(C\) as the centre, then the area (in sq. units) of the quadrilateral \(P A C B\) is
- A \(2 \sqrt{g}\)
- B \(\sqrt{g^3-4 g}\)
- C \(\sqrt{g^3+4 g}\)
- D \(\sqrt{\frac{g^3}{2}+4 g}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{g^3+4 g}\)
Step-by-step Solution
Detailed explanation
Given, from point \(P(1,1)\), tangent \(P A\) and \(P B\) is drawn \(\therefore \quad P A=\sqrt{S_1} \Rightarrow P A=\sqrt{1+1+g+g-2}=\sqrt{2 g}\) Radius of circle \(=\sqrt{\frac{g^2}{4}+\frac{g^2}{4}+2} \Rightarrow A C=\frac{1}{\sqrt{2}} \sqrt{g^2+4}\) \(\therefore\) Area of…
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