TS EAMCET · Physics · Mechanical Properties of Fluids
A large tank filled with water to a height \(h\) is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from \(h\) to \(h / 2\) and \(h / 2\) to zero is
- A \(\sqrt{2}\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(\sqrt{2}-1\)
- D \(\frac{1}{\sqrt{2-1}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{2}-1\)
Step-by-step Solution
Detailed explanation
Time taken, \(t=\sqrt{\frac{2 h}{g}}\) Time taken for the level of water to fall from \(h\) to \(h / 2\) to 0 , \(t_1=\sqrt{\frac{2}{g}}\left(\sqrt{h_1}-\sqrt{h_2}\right)\) \(=\sqrt{\frac{2}{g}}\left(\sqrt{h}-\sqrt{\frac{h}{2}}\right)\)…
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