TS EAMCET · Physics · Dual Nature of Matter
The de-Broglie wavelength associated with an electron, accelerated through a potential difference of 121 volts is about: [Take Plank's constant \(=\mathrm{h}=6.6 \times 10^{-34} \mathrm{~J} . \mathrm{s}\), mass of electron \(9 \times 10^{-31} \mathrm{~kg}\) ]
- A \(0.123 \mathrm{~nm}\)
- B \(0.112 \mathrm{~nm}\)
- C \(0.221 \mathrm{~nm}\)
- D \(0.098 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(B) \(0.112 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
de-Broglie wavelength \[ \begin{aligned} & \lambda=\frac{\mathrm{h}}{\mathrm{p}}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{meV}}} \\ & =\frac{6.6 \times 10^{-34}}{\sqrt{2 \times 9 \times 10^{-31} \times 1.6 \times 10^{-19} \times 121}}=0.112 \mathrm{~nm} \end{aligned} \]
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