TS EAMCET · Chemistry · Structure of Atom
The threshold frequency of a metal is \(10^{15} \mathrm{~s}^{-1}\). The ratio of maximum kinetic energies of the photoelectrons, when the metal is made to strike with radiations of frequencies \(1.5 \times 10^{15} \mathrm{~s}^{-1}\) and \(2.0 \times 10^{15} \mathrm{~s}^{-1}\) respectively is
- A \(2:1\)
- B \(1:2\)
- C \(4:3\)
- D \(3:4\)
Answer & Solution
Correct Answer
(B) \(1:2\)
Step-by-step Solution
Detailed explanation
\(v_0=1.0 \times 10^{15} \mathrm{~s}^{-1}\) Maximum kinetic energy will be at the highest frequencies and when all the energy is utilized for the kinetic energy of the ejected electrons:…
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