TS EAMCET · Chemistry · Some Basic Concepts of Chemistry

$1.5 \mathrm{~g}$ of $\mathrm{CdCl}_2$ was found to contain $0.9 \mathrm{~g}$ of $\mathrm{Cd}$. Calculate the atomic weight of Cd.

A 118
B 112
C 106.5
D 53.25

Verified Solution

Answer & Solution

Correct Answer

(C) 106.5

Step-by-step Solution

Detailed explanation

$\begin{aligned} \% \text { of } \mathrm{Cd} \text { in } \mathrm{CdCl}_2= & \frac{0.9}{1.5} \times 100 \\ & =60 \% \end{aligned}$ Therefore, $\%$ of $\mathrm{Cl}_2$ in $\mathrm{CdCl}_2=100-60=40 \%$…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match the following

Column-1 Reaction		Column-2 Main product
A)	$4 {FeCl}_{3} + 3 K_{4} [Fe (CN)_{6}] \to$	I)	${Fe}_{4} {[Fe (CN)_{6}]}_{3}$
B)	${ZnCl}_{2} + 4 NaOH \to$	II)	${FeCl}_{2}$
C)	$2 {FeCl}_{3} + H_{2} S \to$	III)	$Zn (OH) Cl$
		IV)	${Fe}_{3} {[Fe (CN)_{6}]}_{3}$
		V)	${Na}_{2} {ZnO}_{2}$
		VI)	$FeS$

TS EAMCET 2021 Hard

Explore more questions on app

From TS EAMCET

Explore more questions on app

\(1.5 \mathrm{~g}\) of \(\mathrm{CdCl}_2\) was found to contain \(0.9 \mathrm{~g}\) of \(\mathrm{Cd}\). Calculate the atomic weight of Cd.

Answer & Solution

Step-by-step Solution

See the Complete Solution