TS EAMCET · Maths · Trigonometric Equations
The common solution set of the equations \(2 \sin ^2 x+\sin ^2 2 x=2\) and \(\sin 2 x+\cos 2 x=\tan x\) is
- A \(\left\{x \in R: x=(2 n+1) \frac{\pi}{4}, n \in Z\right\}\)
- B \(\left\{x \in R: x=(3 n+1) \frac{\pi}{4}, n \in Z\right\}\)
- C \(\left\{x \in R: x=(4 n+1) \frac{\pi}{8}, n \in Z\right\}\)
- D \(\left\{x \in R: x=(4 n-1) \frac{\pi}{8}, n \in Z\right\}\)
Answer & Solution
Correct Answer
(A) \(\left\{x \in R: x=(2 n+1) \frac{\pi}{4}, n \in Z\right\}\)
Step-by-step Solution
Detailed explanation
\(\left\{x \in R: x=(2 n+1) \frac{\pi}{4}, n \in Z\right\}\) \(2 \sin ^2 x+\sin ^2 2 x=2\) ...(i) and \(\sin 2 x+\cos 2 x=\tan x\) ...(ii) From Eq. (i),…
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