TS EAMCET · Physics · Semiconductors
Current I through a given \(\mathrm{p}-\mathrm{n}\) junction when a voltage \(\mathrm{V}\) is applied across it is given to be \(\mathrm{I}=\mathrm{I}_0\left(e^{\frac{V}{2 V_T}}-1\right)\) where \(I_0\) and \(V_T\) are constants. If \(r_d(I)\) is the dynamic resistance of the junction, then \(r_d\left(1000 I_0\right)=\alpha r_d\left(10 I_0\right)\), where \(\alpha\) is approximately equal to
- A 10
- B \(1 / 10\)
- C \(1 / 100\)
- D \(1 / 1000\)
Answer & Solution
Correct Answer
(C) \(1 / 100\)
Step-by-step Solution
Detailed explanation
We have Dynamic resistance \(r_d(I)=\frac{\text { Change in voltage }}{\text { Change in current }}\) Give \(r_d\left(1000 I_0\right)=\alpha r_d\left(100 I_0\right)\)…
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