TS EAMCET · Physics · Current Electricity
For the circuit shown in the figure, the current through \(6 \Omega\) resistor connected between the junctions A and B is
- A 0.25 A
- B 0.5 A
- C 0.75 A
- D 0.4 A
Answer & Solution
Correct Answer
(B) 0.5 A
Step-by-step Solution
Detailed explanation
KCL at A: \(\frac{V_A - 10}{4} + \frac{V_A - V_B}{6} + \frac{V_A}{4} = 0\) KCL at B: \(\frac{V_B - V_A}{6} + \frac{V_B}{4} + \frac{V_B - 20}{4} = 0\) Simplifying equations: \(8V_A - 2V_B = 30 \implies 4V_A - V_B = 15\) \(-2V_A + 8V_B = 60 \implies -V_A + 4V_B = 30\) Solving the…
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