TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
The correct decreasing order of the following 'Xe' compounds to act as both fluorinating and oxidizing agent is (i) \(\mathrm{XeF}_6\) (ii) \(\mathrm{XeF}_4\) (iii) \(\mathrm{XeF}_2\)
- A \(\mathrm{XeF}_2>\mathrm{XeF}_4>\mathrm{XeF}_6\)
- B \(\mathrm{XeF}_6>\mathrm{XeF}_4>\mathrm{XeF}_2\)
- C \(\mathrm{XeF}_4>\mathrm{XeF}_6>\mathrm{XeF}_2\)
- D \(\mathrm{XeF}_6>\mathrm{XeF}_4>\mathrm{XeF}_2\)
Answer & Solution
Correct Answer
(B) \(\mathrm{XeF}_6>\mathrm{XeF}_4>\mathrm{XeF}_2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{XeF}_6: \mathrm{Xe}\) is in the highest oxidation state (O.S.) \(\mathrm{XeF}_2: \mathrm{Xe}\) is in the lowest O.S. \(\therefore \quad \mathrm{XeF}_6\) has the highest tendency to get reduced itself. Therefore, it acts as, the strongest oxidizing agent. Whereas…
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