TS EAMCET · Physics · Wave Optics
The Brewster angle for air to glass transition of light is (Refractive index of glass \(=1.5\) ).
- A \(\sin ^{-1}\left(\frac{3}{2}\right)\)
- B \(\cos ^{-1}\left(\frac{3}{2}\right)\)
- C \(\tan ^{-1}\left(\frac{3}{2}\right)\)
- D \(\cos ^{-1}\left(\frac{2}{3}\right)\)
Answer & Solution
Correct Answer
(C) \(\tan ^{-1}\left(\frac{3}{2}\right)\)
Step-by-step Solution
Detailed explanation
Brewster's angle, \(i_p=\tan ^{-1}(\mu)=\tan ^{-1}(1.5)\) \(=\tan ^{-1}\left(\frac{3}{2}\right)\)
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