TS EAMCET · Chemistry · Chemical Kinetics
For the gaseous reaction, \(\mathrm{N}_2 \mathrm{O}_5 \rightarrow 2 \mathrm{NO}_2+\frac{1}{2} \mathrm{O}_2\) the rate can be expressed as
\( -\frac{\mathrm{d}\left[\mathrm{N}_2 \mathrm{O}_5\right]}{\mathrm{dt}}=\mathrm{K}_1\left[\mathrm{~N}_2 \mathrm{O}_5\right] \ +\frac{\mathrm{d}\left[\mathrm{NO}_2\right]}{\mathrm{dt}}=\mathrm{K}_2\left[\mathrm{~N}_2 \mathrm{O}_5\right] \ +\frac{\mathrm{d}\left[\mathrm{O}_2\right]}{\mathrm{dt}}=\mathrm{K}_3\left[\mathrm{~N}_2 \mathrm{O}_5\right]\) The correct relation between \(\mathrm{K}_1, \mathrm{~K}_2\) and \(\mathrm{K}_3\) is
- A \(\mathrm{K}_1=2 \mathrm{~K}_2=4 \mathrm{~K}_3\)
- B \(2 \mathrm{~K}_1=\mathrm{K}_2=4 \mathrm{~K}_3\)
- C \(2 \mathrm{~K}_1=3 \mathrm{~K}_2=4 \mathrm{~K}_3\)
- D \(4 \mathrm{~K}_1=2 \mathrm{~K}_2=\mathrm{K}_3\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{~K}_1=\mathrm{K}_2=4 \mathrm{~K}_3\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \mathrm{N}_2 \mathrm{O}_5 \rightarrow 2 \mathrm{NO}_2+\frac{1}{2} \mathrm{O}_2 \\ & \text { Rate of reaction }=-\frac{\mathrm{d}\left[\mathrm{N}_2 \mathrm{O}_5\right]}{\mathrm{dt}}=\frac{1}{2}…
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