TS EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta, \gamma\) are the roots of the equation \(4 x^3-3 x^2+2 x-1=0\), then \(\alpha^3+\beta^3+\gamma^3=\)
- A \(\frac{2}{27}\)
- B \(\frac{1}{8}\)
- C \(\frac{3}{64}\)
- D \(\frac{27}{128}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{64}\)
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Detailed explanation
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