ExamBro
ExamBro
TS EAMCET · Chemistry · Electrochemistry

The reduction potential of a half cell consisting of a Pt electrode immersed in \(2.0 \mathrm{M} \mathrm{Fe}^{2+}\) and \(0.02 \mathrm{M} \mathrm{Fe}^{3+}\) solution (in V) is Given \(\left(\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059, \mathrm{E}_{\mathrm{Fe}^{3+} \mid \mathrm{Fe}^{2+}}^0=0.771 \mathrm{~V}\right)\)

  1. A 0.543
  2. B 0.653
  3. C 0.733
  4. D 0.822
Verified Solution

Answer & Solution

Correct Answer

(B) 0.653

Step-by-step Solution

Detailed explanation

\(\mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+}\) Using Nernst equation,…