TS EAMCET · Maths · Matrices
If \(A=\left[\begin{array}{lll}1 & 0 & 1 \\ 2 & 1 & 0 \\ 3 & 2 & 1\end{array}\right]\), then det \(A\) is equal to
- A \(2\)
- B \(5\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} |A| & =\left|\begin{array}{lll} 1 & 0 & 1 \\ 2 & 1 & 0 \\ 3 & 2 & 1 \end{array}\right|=1(1-0)+0+1(4-3) \\ & =1+1=2 \end{aligned} \]
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