TS EAMCET · Chemistry · Chemical Kinetics
In a first order reaction, the concentration of the reactant decrease from \(0.6 \mathrm{M}\) to \(0.3 \mathrm{M}\) in \(15 \mathrm{~min}\). The time taken for the concentration to change from \(0.1 \mathrm{M}\) to \(0.025 \mathrm{M}\) in minutes is
- A \(1.2\)
- B \(12\)
- C \(30\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(30\)
Step-by-step Solution
Detailed explanation
Since, concentration of the reactant decreases from \(0.6 \mathrm{M}\) to \(0.3 \mathrm{M}\) (i.e., halved) in 15 minutes, therefore half time for this reaction be \(15 \mathrm{~min}\). \[ \text { i.e. }, t_{1 / 2}=15 \mathrm{~min} \] Now for a first order reaction…
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