TS EAMCET · Maths · Differentiation
If \(\cos ^{-1}\left(\frac{x^2-y^2}{x^2+y^2}\right)=k\) (a constant), then \(\frac{d y}{d x}\) is equal to
- A \(\frac{y}{x}\)
- B \(\frac{x}{y}\)
- C \(\frac{x^2}{y^2}\)
- D \(\frac{y^2}{x^2}\)
Answer & Solution
Correct Answer
(A) \(\frac{y}{x}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Given, } \cos ^{-1}\left(\frac{x^2-y^2}{x^2+y^2}\right)=k \\ & \Rightarrow \quad \frac{x^2-y^2}{x^2+y^2}=\cos k \end{aligned}\) On differentiating w.r.t. \(x\), we get…
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