TS EAMCET · Maths · Complex Number
If \(\alpha, \beta\) are the roots of the equation \(x^2+x+1=0\), then \((\alpha+\beta)^2+\left(\alpha^2+\beta^2\right)^2+\left(\alpha^3+\beta^3\right)^2+\ldots+\left(\alpha^{12}+\beta^{12}\right)^2=\)
- A 48
- B 12
- C 24
- D 36
Answer & Solution
Correct Answer
(C) 24
Step-by-step Solution
Detailed explanation
Since, roots of equation \(x^2+x+1=0\) are complex cube roots of unity…
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