TS EAMCET · Maths · Quadratic Equation
Consider the curves given by the following quadratic function. \(\begin{array}{ll}f_1(x)=5 x^2+2 x+1, & f_2(x)=5 x^2+6 x+1 \ f_3(x)=x^2-7 x+6, & f_4(x)=64 x^2+48 x+9\end{array}\) If \(A_1, A_2, A_3\) and \(A_4\) denote the lengths of the intercepts on the \(X\)-axis made by the above curve respectively, then which of the following is true?
- A \(A_1>A_2>A_3>A_4>0\)
- B \(A_4 < A_2 < A_3\)
- C \(A_3 < A_2 < A_4\)
- D \(A_2 < A_4 < A_3\)
Answer & Solution
Correct Answer
(B) \(A_4 < A_2 < A_3\)
Step-by-step Solution
Detailed explanation
Since, length of the intercept on the \(X\)-axis made by the curve \(f(x)=a x^2+b x+c\) is \(A=\left|x_1-x_2\right|=\frac{\sqrt{D}}{|a|}\), where \(D=b^2-4 a c\) So, for curve \(f_1(x)=5 x^2+2 x+1\), \(A_1=\frac{\sqrt{4-20}}{5}=\frac{\sqrt{-16}}{5}\), not exist For curve…
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