KCET · Physics · Mathematics in Physics
The resultant of two forces acting at an angle of \(120^{\circ}\) is \(10 \mathrm{~kg}\)-wt and is perpendicular to one of the forces. That force is
- A \(10 \sqrt{3} \mathrm{~kg}\)-wt
- B \(20 \sqrt{3} \mathrm{~kg}\)-wt
- C \(10 \mathrm{~kg}-\mathrm{wt}\)
- D \(\frac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{wt}\)
Answer & Solution
Correct Answer
(D) \(\frac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{wt}\)
Step-by-step Solution
Detailed explanation
Here,
\(\begin{gathered}\tan 30^{\circ}=\frac{1}{\sqrt{3}} \\\frac{1}{\sqrt{3}}=\frac{x}{10} \\x=\frac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{wt}\end{gathered}\)
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