KCET · Chemistry · Electrochemistry
The electronegativities of \( \mathrm{C}, \mathrm{N}, \mathrm{Si} \) and \( \mathrm{P} \) are in the order of
- A \( P < S i < C < N \)
- B \( \mathrm{Si} < \mathrm{P} < \mathrm{N} < \mathrm{C} \)
- C \( \mathrm{Si} < \mathrm{P} < \mathrm{C} < \mathrm{N} \)
- D \( P < S i < N < C \)
Answer & Solution
Correct Answer
(C) \( \mathrm{Si} < \mathrm{P} < \mathrm{C} < \mathrm{N} \)
Step-by-step Solution
Detailed explanation
Electronegativity increases along a period and decreases down the group. Nitrogen is expected to have maximum
electronegativity.
Therefore, correct increasing order of electronegativity is \( \mathrm{Si} < \mathrm{P} < \mathrm{C} < \mathrm{N} \).
electronegativity.
Therefore, correct increasing order of electronegativity is \( \mathrm{Si} < \mathrm{P} < \mathrm{C} < \mathrm{N} \).
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