KCET · Chemistry · Chemical Kinetics
For a reaction, the value of rate constant at \(300 \mathrm{~K}\) is \(6.0 \times 10^5 \mathrm{~s}^{-1}\). The value of Arrhenius factor \(A\) at infinitely high temperature is
- A \(6 * 10^5 \times e^{-E_a / 300 R}\)
- B \(e^{-E_a / 300 R}\)
- C \(\frac{6 \times 10^{-5}}{300}\)
- D \(6 \times 10^5\)
Answer & Solution
Correct Answer
(D) \(6 \times 10^5\)
Step-by-step Solution
Detailed explanation
Given, \(k=6 \times 10^5 \mathrm{~s}^{-1}\)
Using the formula of Arrhenius equation, \(k=e^{E_a / R T}\)
At \(T=\alpha, \frac{-E_a}{R T}\) will become zero.
So, \(k=A e^0 \Rightarrow k=A\)
Thus, \(k=A=6 \times 10^5\)
Using the formula of Arrhenius equation, \(k=e^{E_a / R T}\)
At \(T=\alpha, \frac{-E_a}{R T}\) will become zero.
So, \(k=A e^0 \Rightarrow k=A\)
Thus, \(k=A=6 \times 10^5\)
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