KCET · Physics · Thermodynamics
During an adiabatic process, the cube of the pressure is found to be inversely proportional to the fourth power of the volume. Then the ratio of specific heats is
- A 1
- B \(1.33\)
- C \(1.67\)
- D \(1.4\)
Answer & Solution
Correct Answer
(B) \(1.33\)
Step-by-step Solution
Detailed explanation
Equation of an adiabatic process is
\(p V^{\gamma}=\text { constant }\)
Given, \(p^{3}=\frac{k}{V^{4}}\)
\(p^{3} V^{4}=k\)
(constant)
\(\Rightarrow p V^{4 / 3}=k\) Comparing Eqs. (i) and (ii), we get \( \gamma=\frac{4}{3}=1.33 \)
\(p V^{\gamma}=\text { constant }\)
Given, \(p^{3}=\frac{k}{V^{4}}\)
\(p^{3} V^{4}=k\)
(constant)
\(\Rightarrow p V^{4 / 3}=k\) Comparing Eqs. (i) and (ii), we get \( \gamma=\frac{4}{3}=1.33 \)
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